Hi,
This is my basic sql shape query:
----
SHAPE {select * from tbl1}
APPEND({SELECT * FROM tbl2 where field1=1} AS RS2 RELATE field TO
field)
----
With this query i get a RecordSet (RS1), who handle all the records
from table tbl1, and a secondary RecordSet (RS2) who handle all the
records from table tbl2, who applies to the criteria that field1=1.
It is possible that RS2 will be empty (zero records) since there is no
record in tbl2 who applies to that criteria.
My wish is to design a query, that will collect only the records from
tbl1, that will have records from tbl2 who applies to the criteria -
that RS2 won't be empty !
I want to influence on the main part of the query (RS1), through the
criteria that is being used in the secondery query (RS2).
I hope that my question is clear enough. thanks !SHAPE is not a TSQL language element. If I'm not mistaken, it is implemented
in ADO. I have a
feeling that you will get better assistance if you post to a ADO group.
Tibor Karaszi, SQL Server MVP
http://www.karaszi.com/sqlserver/default.asp
http://www.solidqualitylearning.com/
Blog: http://solidqualitylearning.com/blogs/tibor/
<doar123@.gmail.com> wrote in message news:1137102448.006011.123840@.g43g2000cwa.googlegroups
.com...
> Hi,
> This is my basic sql shape query:
> ----
> SHAPE {select * from tbl1}
> APPEND({SELECT * FROM tbl2 where field1=1} AS RS2 RELATE field TO
> field)
> ----
> With this query i get a RecordSet (RS1), who handle all the records
> from table tbl1, and a secondary RecordSet (RS2) who handle all the
> records from table tbl2, who applies to the criteria that field1=1.
> It is possible that RS2 will be empty (zero records) since there is no
> record in tbl2 who applies to that criteria.
> My wish is to design a query, that will collect only the records from
> tbl1, that will have records from tbl2 who applies to the criteria -
> that RS2 won't be empty !
> I want to influence on the main part of the query (RS1), through the
> criteria that is being used in the secondery query (RS2).
> I hope that my question is clear enough. thanks !
>
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